|a = b;||ordinary assignment||copy the value of b into a. If b is reference copy the pointer to b into a, not the values of the fields of the object pointed to by b into the fields of the object currently pointed to by a.|
|a += 2;||a = a + 2;||plus|
|a -= 2;||a = a - 2;||subtract|
|a *= 2;||a = a * 2;||multiply|
|a /= 2;||a = a / 2;||divide|
|a %= 2;||a = a % 2;||modulus|
|a >>>= 2;||a = a >>> 2;||unsigned right shift|
|a >>= 2;||a = a >> 2;||signed right shift|
|a <<= 2;||a = a << 2;||signed and unsigned left shift|
|a &= 2;||a = a & 2;||bitwise and|
|a |= 2;||a = a | 2;||bitwise or|
|a ^= 2;||a = a ^ 2;||xor, exclusive or|
swimmer = swimner + 2;
When you write:
swimmer += 2;
there is no possibility for that sort of leaping to conclusions. Further, even a mindless compiler will generate more efficient code with the compound form.
The offical term for the calculating assignment operators is compound assignment operators.
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